An expansion fitting is required in an 80' run of Schedule 40 PVC because it would expand ___ inches between winter and summer when temperatures change from -5°F to 100°F.

An expansion fitting is required in an 80' run of Schedule 40 PVC because it would expand ___ inches between winter and summer when temperatures change from -5°F to 100°F.

• A. 5.325
• B. 3.85
• C. 3.408
• D. 4.26

Answer: (C)

To determine the amount an 80-foot run of Schedule 40 PVC will expand due to temperature changes from -5°F to 100°F, it’s important to understand how thermal expansion works for materials. The coefficient of linear thermal expansion for PVC is approximately 3.0 x 10^-5 inches per inch per degree Fahrenheit. First, calculate the temperature change: - From -5°F to 100°F is a change of 100 - (-5) = 105°F. Next, apply the formula for linear expansion: Expansion = original length × coefficient of thermal expansion × temperature change. - The original length is 80 feet, which is 80 x 12 = 960 inches. Now, plug in the values: - Expansion = 960 inches × (3.0 x 10^-5 inches/inch/°F) × 105°F. - Expansion = 960 × 3.0 x 10^-5 × 105. Calculating that gives: - Expansion = 960 × 0.000030 × 105 = 0.3024 inches (this seems to be the counting error from steps, we should re-calculate the values correctly). Upon correctly calculating the values for thermal expansion,

To determine the amount an 80-foot run of Schedule 40 PVC will expand due to temperature changes from -5°F to 100°F, it’s important to understand how thermal expansion works for materials. The coefficient of linear thermal expansion for PVC is approximately 3.0 x 10^-5 inches per inch per degree Fahrenheit.

First, calculate the temperature change:

• From -5°F to 100°F is a change of 100 - (-5) = 105°F.

Next, apply the formula for linear expansion:

Expansion = original length × coefficient of thermal expansion × temperature change.

• The original length is 80 feet, which is 80 x 12 = 960 inches.

Now, plug in the values:

• Expansion = 960 inches × (3.0 x 10^-5 inches/inch/°F) × 105°F.

• Expansion = 960 × 3.0 x 10^-5 × 105.

Calculating that gives:

• Expansion = 960 × 0.000030 × 105 = 0.3024 inches (this seems to be the counting error from steps, we should re-calculate the values correctly).

Upon correctly calculating the values for thermal expansion,